http://www.perlmonks.org?node_id=813123


in reply to running a perl file from within a perl file

# 813119.pl: my @args=(0); my $ filename = "ABC.pl"; @args = ("$filename com1@115200 65"); system(@args) == 0 or die "system @args failed: $?";

# ABC.pl: print join( ' / ', @ARGV), "\n";
Mostly works for me. ABC.pl gets called, and displays
com1 / 65
I'd recommend quoting the '@' character in your @args assignment, as in:
@args = ("$filename com1\@115200 65");
Which changes the output to
com1@115200 / 65
What output are you seeing? Which version of perl (perl -V)?

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Re^2: running a perl file from within a perl file
by perly_newbie (Novice) on Dec 18, 2009 at 03:41 UTC
    Hey thanks, for the reply I got it to work.