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Re: perl subtractionby swampyankee (Parson) |
| on Jan 10, 2010 at 20:24 UTC ( #816636=note: print w/ replies, xml ) | Need Help?? |
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You've just run into a problem that computer programmers have dealt with for decades: floating point numbers do not form a closed set under the operations of normal arithmetic. The reason is, of course, that floating point numbers only represent a finite subset of rational numbers.
In Section
Seekers of Perl Wisdom
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