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Re^2: The golf course looks great, my swing feels good, I like my chances (Part VI)

by eyepopslikeamosquito (Canon)
on Mar 06, 2010 at 04:31 UTC ( #827094=note: print w/ replies, xml ) Need Help??


in reply to Re: The golf course looks great, my swing feels good, I like my chances (Part VI)
in thread The golf course looks great, my swing feels good, I like my chances (Part VI)

While I'm still able to remember, I list below the other new (albeit unsuccessful) Ruby solutions I found while searching for the elusive 111 stroker. It's possible I've missed something and one of these attempts might be transformed from a loser into a winner.

The following solutions are all of a similar form to the original 111 stroker, namely:

r=*$<;'XXXXXXXXXXXX'.each_byte{|i|$><<"%#{327%i/9}c"% 'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]+$/*(i/85)}
where XXXXXXXXXXXX above is a string with ord values 120, 47, 253, 22, 194, 21, 183, 44, 196, 55, 125, 246. For clarity below, I show only the 'hxmo'[expr] expressions:
'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11] 'ohmx'[1>>(i-r.to_i)%12^2&2<<i%12-r[3,2].to_i/5] 'hxmo'[(i-r.to_i)%12/-i^0**(i%12^r[3,2].to_i/5)] 'mxho'[1>>(i-r.to_i)%12^(i%12^r[3,2].to_i/5)/-i] 'mxho'[(r[3,2].to_i/5-i)%12/-i^1>>(r.to_i-i)%12] 'hxmo'[(i-r.to_i)%12/-i^1>>(2*r[3]+r[4]/53-i)%12] 'mxho'[(2*r[3]+r[4]/53-i)%12/-i^1>>(i-r.to_i)%12] 'ohmx'[1>>(i-r.to_i)%12^(i%12==r[3,2].to_i/5).id]

And here are some other random attempts:

r=*$<;'XXXXXXXXXXXX'.each_byte{|i|printf"%*c"+$/*(i/85), 327%i/9,'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]} r=*$<;'XXXXXXXXXXXX'.each_byte{|i|$><<" "*(318%i/9)+ 'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11,1]+$/*(i/85)} /:/!~gets;'XXXXXXXXXXXX'.each_byte{|i|$><<"%#{327%i/9}c"% 'hxmo'[(i-$_.to_i)%12/~i^~$'.to_i/5%i%12/11]+$/*(i/85)} r=*$<;$><<"%#{327%J/9}c"%'hxmo'[~r[3,2].to_i/5%J%12/11^ (J-r.to_i)%12/~J]+$/*(J/85)while J='ohXXXXXXXXXXXX'[$.+=1] r=*$<;loop{i="hmXXXXXXXXXXXX"[$.+=1];$><<"%#{327%i/9}c"% 'hxmo'[(i-r.to_i)%12/~i^~r[3,2].to_i/5%i%12/11]+$/*(i/85)} r=*$<;'XXXXXXXXXXXX'.each_byte{|i|$><<"%*c"%[327%i/9, (i%12==r.to_i%12??x:?o)&(i%12==r[3,2].to_i/5??}:?o)]+$/*(i/85)} gets=~/:/;'XXXXXXXXXXXX'.each_byte{|i|print" "*(318%i/9), (111+(i%12==$_.to_i%12?9:0)&111+(i%12==$'.to_i/5?14:0)).chr,$/*(i/85)}
Note that in the solutions above using 318 rather than 327, the XXXXXXXXXXXX string is a string with ord values: 120, 47, 253, 22, 194, 9, 183, 44, 196, 55, 125, 246.


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