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Re^2: Namespace error while parsing html document.

by mr_p (Scribe)
on Jul 01, 2010 at 13:25 UTC ( #847511=note: print w/replies, xml ) Need Help??


in reply to Re: Namespace error while parsing html document.
in thread Namespace error while parsing html document.

Do you know why I was not able to pass $content->{_content} to parse_html_string(), It was blank. Isn't $content->{_content} suppose to have the the file downloaded?

Also,

The only reason I need to load the html page is because I wanted to parse stylesheet link out. For Instance:

Can I use RegExp to parse the below string? I would need to parse all three hrefs in to array.

<?xml-stylesheet href="perl1.css" type="text/css"?> <link href="//www.perl.org/css/perl1.css" rel="stylesheet"> <link href="/css/perl.css" rel="stylesheet">

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Re^3: Namespace error while parsing html document.
by ikegami (Pope) on Jul 01, 2010 at 17:43 UTC

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[hippo]: Understood. I'll have to go through the code and see if it's doing anything fancy with ties, dual-vars or non-scalars. In the end, it's probably a bug though.
[Corion]: Aaah - you should be able to do this with overload, but I would hit somebody really hard if they constructed objects that are true but the empty string, and you not knowing about the domain knowledge where this makes sense
[Eily]: you could tie a variable into not having the same value each time, if you like to make people who try to debug your code facepalm
[Corion]: perl -wle 'package o; use overload q("") => sub {warn "str"; ""}, bool => sub{warn "bool"; 1}; package main; my $o={}; bless $o => o; print "Yay" if ($o && !length($o))'
[Corion]: But people writing such code should document the objects they construct and why it makes sense for an object to be invisible as string while being true in a boolean context
[hippo]: That's equal parts clever and horrendous.
[Eily]: the overload version wouldn't return true with "$x" && !length $x though, I guess
[hippo]: The more I look at this code, the more $x is a plain old scalar and the more this condition will never be true. I'm calling it a bug at this point.
[hippo]: Thanks for your input which has soothed my sanity (a little)
[Corion]: Eily: Sure - if you force both things into stringy things, then you break that magic. But that would also mean that you changed the expression, as now $x = 0.00 will be true instead of false as it were before

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