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Re^3: XML::Simple, XMLOut() question

by samarzone (Pilgrim)
on Dec 15, 2010 at 15:04 UTC ( #877287=note: print w/ replies, xml ) Need Help??


in reply to Re^2: XML::Simple, XMLOut() question
in thread XML::Simple, XMLOut() question

You need not loop. Following would suffice

$x->{user}->{favorites} = {item => $x->{user}->{favorites}};

where $x is your original structure


-- Regards - Samar


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Re^4: XML::Simple, XMLOut() question
by duesouth (Initiate) on Dec 15, 2010 at 16:17 UTC
    Many thanks, that's done the trick.

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