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### Re: (Golf) Kaprekar's Process

by MeowChow (Vicar)
 on Jun 16, 2001 at 23:00 UTC ( #89081=note: print w/replies, xml ) Need Help??

in reply to (Golf) Kaprekar's Process

The answers given thus far all fail on numbers (such as 100 and 211) which generate two-digit numbers in their intermediate results. Here's a good test for this particular golf:
\$| = 1; for (100..999) { next if /(.)\1\1/; print "\$_ : ", k(\$_), \$/; }
And here's a correct solution at 74 68 63 chars:
sub k { \$_=sprintf"%03d",pop;/495/?0:1+k(-(\$_=join'',sort/./g)+reverse) }
MeowChow
s aamecha.s a..a\u\$&owag.print

Replies are listed 'Best First'.
Re: Re: (Golf) Kaprekar's Process
by Anonymous Monk on Jun 17, 2001 at 00:47 UTC
sub k { \$_="000"|"@{[pop]}";/495/?0:1+k(-(\$_=join('',sort/./g)+reverse) }
62

--sean
Verrrry cool idea... this can actually come down to 56:
sub k { \$_="000"|"@_";/495/?0:1+k(-(\$_=join'',sort/./g)+reverse) }
The interesting thing about this is that it's not the same as right-formatting the number via sprintf, since the 0 goes to the back, but it doesn't matter because the digits are reordered anyway.
MeowChow
s aamecha.s a..a\u\$&owag.print
Yeah, i realized the whole @{[pop]} bit wasn't needed about 20 miles from home, figured someone would've already noticed it by the time i got back.. Here's one more:
sub k { \$_=0 x3|"@_";/495/?0:1+k(-(\$_=join'',sort/./g)+reverse) }
55

--sean
Nope..
by sean (Beadle) on Jun 18, 2001 at 09:01 UTC

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