Pulling JAPH out of the iterated SHA512 of the code...

Greetings!

I realized that my previous JAPH was thoroughly unattractive because you had to squint in order to decipher it, which isn't pleasant. That's why I came up with this one. It is based on the same idea of extracting JAPH one character at a time from successive iterations of the SHA512 of the code, but now features whitespaces(!) and pretty symmetrical subroutines. I hope you have as much fun understanding it as I had writing it. Here it is:

use strict;
use Digest::SHA substr(q/=sha512(\/), $/, q);

%_ = (undef($/) && (open *q, $0)
   => undef($/) || ($/=<q>) !~ s+= \w\+=+= =+??? : 6);

$/ =~ s+[\xD\xA]\++\xA+g;
$_ = aJcpbneUbBdThmaWbMqehybAhIkAaPeYavrNcjd0bvb9gxfjay=>;
y #a-zA-Z0-9_$/y #\0->y;#;
y #a-zA-Z0-9_$/y #\0->y;#;

print substr($/=sha512($/), $_, 1) for (map &_ => /./gs);

sub _ ( ) {    #    } ( ) _ dus
sub x ($) { !  q  ! } ($) x dus
{ 0 x (0) rox  !  xor (0) x 0 }
!((//m...//m)  ^  (m\\...m\\))?
(64)x + (ord)  :  (ord) + x(49)
}              #              {
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perl -w it, it runs without warnings and prints exactly "Just another Perl hacker,".

Good start points to understand what happens:

EDIT: Here's an alternative version of the code that doesn't read it's own source, making it more portable (possible use as a one-liner, no trailing whitespace problem) but much less interesting:

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