Re^3: How to call Linux command sequentially

[Utilitarian]

When you call exec a new process is forked and the parent quits, whereas when you call system the parent waits for the system call to complete. Using backticks `` or the qx is similar to a system call but the output is returned to the caller. eg.

$ perl -Mstrict -e 'my @out =qx{ls $ENV{HOME}/tmp}; 
chomp @out;
print join (", " , @out), "\n";'
a.out, test.c, test.dat, test.pl

Could you show us how you call the command within your Perl script?

[[e-mail]]

OK there was syntax problem i was able to run the command. But here comes another problem. The first command here creates the an environment, in that environment i need to execute the second command. Here nither system nor exec will do these. Untill I manually exit from environment the second command is not running. Once i exit from environment the second executes. But i need the second command to be executed in environment which was set by first command. Is it possible to do so? Please help!!!!

[Corion]

See Get default login environment.

[graff]

You could try something like:

#!/usr/bin/perl

use strict;

my $shpid = open( SH, '|-', '/bin/bash' ) or die "Can't launch bash: $
+!\n";

my @command_list = ( 
   "first_command args ...\n",
   "second_command args ...\n"
   ... );

for my $cmd ( @command_list ) {
    print SH $cmd;
}
print SH "exit\n";
waitpid( $shpid, 0 );

If the list of commands actually includes things that change the shell environment for subsequent commands, that should work as intended.