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Re^4: Stumped by Crypt::OpenPGP::Signature->key_id

by mhi (Friar)
on Nov 22, 2011 at 12:14 UTC ( #939445=note: print w/replies, xml ) Need Help??

in reply to Re^3: Stumped by Crypt::OpenPGP::Signature->key_id
in thread Stumped by Crypt::OpenPGP::Signature->key_id

 unpack('H*', $sigobj->key_id) gives me a 16-digit hex number in which I can find no similarity with the Key-ID of the actual key.

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Re^5: Stumped by Crypt::OpenPGP::Signature->key_id
by Anonymous Monk on Nov 22, 2011 at 13:08 UTC

    Now I remember why I linked Crypt OpenPGP Brain twister, its a Short, Self Contained, Correct Example, in otherwords, more effective :)

    If you modify Crypt-OpenPGP-1.06\t\12-sign.t at the first verify call, you can see that this is to be expected

    my( $signer , $sigobj ) = $pgp->verify( Signature => $sig ); use DDS; die Dump( [ $key_id , $sigobj->key_id, unpack('H*', $sigo +bj->key_id ) , pack('H*',$key_id) ] );

    $ARRAY1 = [ '39F560A90D7F1559', "9\365`\251\r\177\25Y", '39f560a90d7f1559', "9\365`\251\r\177\25Y" ];

    I don't know if keyid is supposed to be 8 or 10 or 16, but the round trip with pack seems to work , so key_id is correct, and the hex representation is correct

    AFAIK printf would actually try to convert it, which might overflow as in

    $ perl -le " print 0x39f560a90d7f1559 Integer overflow in hexadecimal number at -e line 1. 4.17635050864817e+018

    Maybe this is the private key, and you're looking for the public key? Maybe it depends on algorithm? :)

      Thank you! A combo of your posts and some further reading on key id formats did it: shows that your upack-suggestion is indeed just what is needed:

      lib/Crypt/OpenPGP/ 106:sub key_id_hex { uc unpack 'H*', $_[0]->key_id }

      I just didn't recognize the result since I was expecting the short key ID format and that outputs the long format.

      The solution is:

      print "KeyID hex long: 0x", uc unpack('H*', $sigobj->key_id) + ,"\n"; print "KeyID hex short: 0x",uc substr( unpack('H*', $sigobj->key_id), +-8, 8),"\n";

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