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Need to capture an optional sub-directory name

by technojosh (Priest)
on Mar 29, 2012 at 15:18 UTC ( #962426=perlquestion: print w/replies, xml ) Need Help??
technojosh has asked for the wisdom of the Perl Monks concerning the following question:

I have a sub I use to build a name of a "test case" during an automation run. This name is a string that includes the directory of the Perl .pl file, as well as the file name with the suffix (.pl) stripped off.

So a file with the path 'C:\Tools\scripts\Test\' would produce the string 'Test - Foo'

here is my current sub, which works for me as long as there is no directory between 'Test' and 'Foo':

sub ScriptName { my ($self) = @_; my $name = Win32::GetFullPathName($0); my $dirChop = substr( $name, index($name,'\\scripts\\')+9 ); my $dir = substr( $dirChop, 0, index($dirChop,'\\') ); my $clean = substr( $name, rindex($name,'\\')+1, rindex($name,'.')-(rindex($name,'\\')+1) ); return "$dir - $clean" }

This will totally ignore the sub-directory in the path 'C:\Tools\scripts\Test\Unstable\', where I would like it to return the string 'Test - Unstable - Foo'... but I am no regex pro.

I am looking for a couple pointers:
  1. Can this be cleaned up with regex?
  2. How can I capture a subdirectory (if it exists) too (without losing current functionality)?

Replies are listed 'Best First'.
Re: Need to capture an optional sub-directory name
by BrowserUk (Pope) on Mar 29, 2012 at 15:28 UTC
    but I am no regex pro

    You don't need to become a "regex pro" -- whatever one of those is -- but you would sure save yourself some time in the long run, by making the effort to learn the basics:

    $p = 'C:\Tools\scripts\Test\Unstable\';; $p =~ s[C:\\Tools\\scripts\\([^.]+).pl][$1]; $p =~ s[\\][ - ]g; print $p;; Test - Unstable - Foo $p2 = 'C:\Tools\scripts\Test\';; $p2 =~ s[C:\\Tools\\scripts\\([^.]+).pl][$1]; $p2 =~ s[\\][ - ]g; print $p2;; Test - Foo

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    The start of some sanity?

Re: Need to capture an optional sub-directory name
by spazm (Monk) on Mar 29, 2012 at 16:26 UTC
    You way want to look into a module like File::Spec or Path::Class that allows manipulation of file paths to use the fact that you know this is a path situation.
    use File::Spec sub SriptName { my ($self) = @_; my $name = Win32::GetFullPathName($0); my ($volume, $dirs, $file ) = File::Spec->splitpath( $name ); my (@dirs) = File::Spec->splitdir( $dirs ); $_ = shift @dirs until $_ eq 'scripts'; #drop all suffix (not sure if this is what you want here) # this could/should also be $file = basename($file) $file =~ s/\..*//; return join( ' - ', @dirs, $file) }
Re: Need to capture an optional sub-directory name
by AnomalousMonk (Chancellor) on Mar 29, 2012 at 18:35 UTC

    A nice module like File::Spec or Path::Class will probably save you some head-hurt, but here's a possible regex approach (needs 5.10+ for \K):

    >perl -wMstrict -le "my @paths = qw( C:\Tools\scripts\Test\ C:\Tools\Test\Unstable\ C:\Tools\scripts\Test\Bar.dir\Baz\ C:\Tools\Test\Baz\Test\ ); ;; my $all_before_Test = qr{ \A (?: (?! \\ Test) .)* }xms; ;; for my $path (@paths) { print qq{'$path'}; my @chunks = $path =~ m{ (?: $all_before_Test | \G) \\ \K [^\\]+ }xmsg; $chunks[-1] =~ s{ [.] [^.]* \z }{}xms; my $msg = join q{ - }, @chunks; print qq{'$msg' \n}; } " 'C:\Tools\scripts\Test\' 'Test - Foo' 'C:\Tools\Test\Unstable\' 'Test - Unstable - Foo' 'C:\Tools\scripts\Test\Bar.dir\Baz\' 'Test - Bar.dir - Baz - Foo' 'C:\Tools\Test\Baz\Test\' 'Test - Baz - Test - Foo'

    If you want 'C:\Tools\Test\Baz\Test\' to render as 'Test - Foo' use
        my $all_before_Test = qr{ \A .* (?= \\ Test) }xms;

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