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Re^3: Introducing MooseX::hasn't

by Arunbear (Parson)
on Apr 03, 2012 at 10:23 UTC ( #963211=note: print w/ replies, xml ) Need Help??


in reply to Re^2: Introducing MooseX::hasn't
in thread Introducing MooseX::hasn't

It breaks the inheritance contract, not polymorphism per se (I think you've got the two concepts confused). Polymorphism doesn't depend on inheritance, e.g. Roles enable polymorphism without inheritance.


Comment on Re^3: Introducing MooseX::hasn't
Re^4: Introducing MooseX::hasn't
by tobyink (Abbot) on Apr 03, 2012 at 13:14 UTC

    No, polymorphism doesn't depend on inheritance, and I never claimed that it did. Polymorphism is generally an expected outcome of inheritance though. There are clearly other ways of allowing polymorphism though - roles as you say; also mocking, delegation, etc.

    perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'
      From the POD:
      The idea behind polymorphism is that if Bar inherits from Foo, then I should be able to use an object of type Bar wherever I'd normally use Foo.
      That makes it sound like you're equating polymorphism with inheritance.

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