|The stupid question is the question not asked|
Re: Perl closures: internal details.(Updated)by dave_the_m (Parson)
|on Apr 12, 2012 at 13:49 UTC||Need Help??|
Ok here's how it works.
Each sub has three phases; compilation, creation, and execution; for named subs, creation happens at the same time as compilation; for anon subs, its later, and there can be multiple creations, which is why they're more interesting.
At compile time, a note is made for each sub, of what outer lexicals it makes use of; at creation time, the sub is given its pad, with the first instance of each of its lexical vars created and stored within; also, a reference to the current instance of each outer lexical is stored in the pad. So the pad contains references to both its own lexical vars and to any outer ones.
On first execution, all the vars are available in the pad. On return from the sub, all the sub's own lexical vars are abandoned, and new empty ones created in the pad, ready for the next execution (if any).
There's a bit more to it than that, but that's the main effect. For more details, looks at pad.c in the perl source: S_pad_findlex() is the main function that does the compile-time stuff; I wrote that about 10 years ago, and don't remember much of what it does any more :-(. Then, Perl_cv_clone() shows what happens at create time for anon subs (the creation for named subs happens in parallel with compilation, and nothing special needs doing for it). Finally, in pp_*.c, the pp_pad?v functions show what happens to a lexical variable on entry to a scope (basically SAVECLEARSV() is called), while in scope.c, the SAVEt_CLEARSV branch of Perl_leave_scope shows what happens on scope exit, including an optimisation to just clear the var in place if nothing else is using it.
Also try running with -DX or -DXv on debugging perl builds.