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Re: Mini-Tutorial: Dereferencing Syntax

by Anonymous Monk
on Jun 21, 2012 at 13:06 UTC ( #977633=note: print w/ replies, xml ) Need Help??

in reply to Mini-Tutorial: Dereferencing Syntax

Not mentioned:   $$foo as shorthand for $foo->.

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Re^2: Mini-Tutorial: Dereferencing Syntax
by ikegami (Pope) on Sep 17, 2012 at 05:03 UTC

    $$foo is not a shorthand for $foo->.

    >perl -E"$foo=\'foo'; say $$foo;" foo >perl -E"$foo=\'foo'; say $foo->;" syntax error at -e line 1, near "->;" Execution of -e aborted due to compilation errors.

    You're probably thinking of the equivalency of $$foo[...] and $foo->[...] and of $$foo{...} and $foo->{...}, but that's already mentioned.

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