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Re^2: Which bit is set? (inverse of (1<<$value) operator)

by wirito (Acolyte)
on Sep 17, 2012 at 12:13 UTC ( #994024=note: print w/ replies, xml ) Need Help??


in reply to Re: Which bit is set? (inverse of (1<<$value) operator)
in thread Which bit is set? (inverse of (1<<$value) operator)

Nope, it's a two-byte int, not a strings filled with 0's and 1's.
  • Comment on Re^2: Which bit is set? (inverse of (1<<$value) operator)

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