But always get between 0 and 1. Any ideas?

Works as designed.

$ perl -e 'use 5.10.0; say int(6*rand())+1 foreach(1..10);'
6
5
4
6
2
2
4
6
3
5

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As MidLifeXis pointed out:

       rand EXPR
       rand    Returns a random fractional number greater than or equa
+l to 0
               and less than the value of EXPR.  (EXPR should be posit
+ive.)
               If EXPR is omitted, the value 1 is used.  Currently EXP
+R with
               the value 0 is also special-cased as 1 (this was undocu
+mented
               before Perl 5.8.0 and is subject to change in future ve
+rsions
               of Perl).  Automatically calls "srand" unless "srand" h
+as
               already been called.  See also "srand".

               Apply "int()" to the value returned by "rand()" if you 
+want
               random integers instead of random fractional numbers.  
+For
               example,

                   int(rand(10))

               returns a random integer between 0 and 9, inclusive.

               (Note: If your rand function consistently returns numbe
+rs that
               are too large or too small, then your version of Perl w
+as
               probably compiled with the wrong number of RANDBITS.)

               "rand()" is not cryptographically secure.  You should n
+ot rely
               on it in security-sensitive situations.  As of this wri
+ting, a
               number of third-party CPAN modules offer random number
               generators intended by their authors to be cryptographi
+cally
               secure, including: Math::Random::Secure,
               Math::Random::MT::Perl, and Math::TrulyRandom.

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