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"23 s stored as a single byte hence i cant split."

Byte?! You're thinking in C terms! Go wash your mouth out with soap right now! ;-)

In Perl, strings and integers are both represented by the same data type - scalars. (Internally Perl represents scalars as a C struct which has separate string and integer slots. But you don't normally need to worry about such concerns.) If you have a variable that contains an integer value, such as 23, and pass it to something that expects a string, like split, that integer will be silently converted to a string.

Here's exactly the same function I posted before, only now I'm using the integer 23 as the input...

use 5.010; use strict; use warnings; # 23 is an integer. # say digit_sum(23); # This expression is used to test that a string consists of a single # digit. We use it a couple of different places, so we'll get define # it once here. # use constant DIGIT => qr/^[0-9]$/; # This is the function which adds digits # sub digit_sum { my $string = shift; # Otherwise, split into digits. my @digits = grep { $_ =~ DIGIT } # keep only the numeric characters split '', $string; # split into characters # Add the digits together. my $sum = 0; $sum += $_ for @digits; # Handle the trivial case. # If $sum is just a single digit, return it as-is. return $sum if $sum =~ DIGIT; # Otherwise, recurse. return digit_sum($sum); }
perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

In reply to Re^5: How to split an integer?? by tobyink
in thread How to split an integer?? by nithins

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