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The ugly truth is both don't work!

eq forces scalar context and is meant to compare strings

So in the first code you are checking if the sizes (after stringification) are equal.

```  DB<107> @a = 1..3
=> (1, 2, 3)

DB<108> @a eq "3"
=> 1

in the second you have scalar from reverse on RHS

```  DB<123> (reverse @a)
=> (3, 2, 1)

DB<124> scalar (reverse @a)
=> 321

DB<125> "321" eq (reverse @a)
=> 1

you can try the (less weird) smart match operator ~~ to compare arrays.

```  DB<129> @a=(3,1,3)
=> (3, 1, 3)

DB<130> @a ~~ [reverse @a]
=> 1

DB<131> @a ~~ [3,1,3]
=> 1

DB<132> @a=1..3
=> (1, 2, 3)

DB<133> @a ~~ [reverse @a]
=> ""

a poor man's solution with eq is to explicitly stringify on both sides.

```  DB<143> @a=(3,1,3)
=> (3, 1, 3)

DB<144> @ar=reverse @a
=> (3, 1, 3)

DB<145> "@a"
=> "3 1 3"

DB<146> "@a" eq "@ar"
=> 1

But this depends on the nature of your array elements, don't be too surprised about:

```  DB<151> "@a"
=> "3 1 3"

DB<152> @b=(3,"1 3")
=> (3, "1 3")

DB<153> "@a" eq "@b"
=> 1

Cheers Rolf

In reply to Re: Palindrome array by LanX
in thread Palindrome array by rnaeye

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