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Syntactic Confectionery Delight

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hi monks,

finding my ways through the vast fields of perl using "intermediate perl" by o'reilly as a guide ... currently, in the middle of not-loosing-my-head while trying to understand the schwartzian transform ... one thing acutally strikes me: the following code is working sweet as:

my @words = qw (Oli Sonni sonja oliver speedy 112); my @output = map $_->[0], sort {$a->[1] cmp $b->[1]} map { my $string = $_; $string =~ tr/A-Z/a-z/; $string =~ tr/a-z//cd; [$_, $string]} @words; for my $word (@output){say $word;}

The output, as expected is a "dictionary"-sorted list (acutllay, that's the solution proposed in the actual book itself): 123 ... Oli ... speedy However, I did come up with quite a similar solution. The only difference is that I stuffed the regexes into a subroutine:

my @words = qw (Oli Sonni sonja oliver speedy 112); my @output = map $_->[0], sort {$a->[1] cmp $b->[1]} map [$_, transform($_)], @words; sub transform{ my $string = shift; $string =~ tr/A-Z/a-z/;#kleinschreibung $string =~ tr/a-z//cd; } for my $word (@output){say $word;}

As a result, I am getting the original sorting of the list. Some enlighted monk being able to see what I do not see ...?

Thanks in advance, Oli

In reply to Schwartzian Transfrom using a subroutine by oliverhuber

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    [Eily]: hu, don't tell the other French people I never tried it, I might get kicked out :P
    choroba . o O ( The Czech at-sign is also edible )
    [Eily]: the French @ is a mouthful I guess...
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    [Eily]: (yes I'm very good at using question marks, thank you)
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    [choroba]: Zavináč

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