I read once that JS-regexes follow the standards of Perl4.
Now I was quite surprised to learn that JS doesn't have a /s single-line modifier to let '.' also match on linebreaks like \n.
As a compensation JS offers to use [^] to match everything (the negation of nothing is everything).
>>> "a <\n \n> z".match('<[^]*>')
I like the concept and was wondering if there is any equivalent in Perl ...
Here [^] is a syntax error because at this position Perl magically expects ']' to be part of the negated char-class and still expects another closing ']'.
The closest that I was able to find was (?:.|\n)
DB<118> "a <\n \n> z" =~ /<(?:.|\n)*>/ ; $ &
=> "<\n \n>"
Any other suggestions?
Another option is to use single-line locally: (see perlrecharclass)
DB<146> "a <\n \n> z" =~ /<(?s:.)*>/;$ &
=> "<\n \n>"
not shorter but cleaner!
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