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If so, your message does not help. Please clarify the question if you think I didn't understand it.

Consider that you didn't miss the point -- in what way does your reply constitute an answer or an explanation?

foo( $blah && $foo ); works to alias $foo

$ref = \($blah && $foo); works to reference $foo

( $blah && $foo ) = foo(); is illegal

Where is this documented? Why is it illegal?

Oh, ikegami says it doesn't return a copy (why would it) -- who asked about a copy ?

In reply to Re^4: Why Perl boolean expression sometimes treated as lvalue? by Anonymous Monk
in thread Why Perl boolean expression sometimes treated as lvalue? by vsespb

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