If you really want a regex-solution (which isn't necessarily the best idea), here's one from the bottom of the poison cabinet:
use strict;
use warnings;
use 5.010;
$_ = '79899920179';
my $pass = qr/(?=)/;
my $fail = qr/(*FAIL)/;
while (/\G(\d{2,}?)(??{ $1 >= 32 ? $pass : $fail })/g) {
say $1;
}
I'm sure that can be simplified somehow, but right now I don't know how.
Be sure to read the warning about (??{...}) in perlre.
And here's a nicer Perl 6 solution:
$ perl6 -e 'say "79899920179".comb(/ (\d **? 2..*) <?{ $0 >= 32 }>/)'
79 89 99 201 79
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