I cannot see where you get N factorial from. To me it seems what you describe is N^2. This is also what I get from the brute force method below:
use strict;
use warnings;
use Time::HiRes qw/time/;
sub find_best_offset {
my $strref = shift;
my $n = length $$strref;
my $mindiff = $n;
my $best_offset = -1;
for( my $i=1; $i<=$n/2; $i++ ) {
# shift/rotate string and compare to original
my $diff = $$strref ^ substr( $$strref, -$i ).substr( $$strref
+, 0, -$i );
# number of differing characters between shifted string and or
+iginal
my $ndiff = $diff =~ tr/\0//c;
# test for and keep optimal solution
if( $ndiff < $mindiff ) {
return $i unless $ndiff; # best case!
$mindiff = $ndiff;
$best_offset = $i;
}
}
return $best_offset;
}
for ( 9, 99, 999, 9999, 99999 ) {
my $t = time;
my $str1 = "01234567890123456789".("01234567890123456x89" x $_);
print find_best_offset( \$str1 );
print "\t$_\t",time-$t,"\n";
}
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