G'day spstansbury,
I see Tux has provided you with a better way to tackle your task.
The reason you're getting the results you see with your posted solution is as follows.
Given this test.csv (newlines shown as "$" and tabs as "^I"):
$ cat -vet test.csv
quote at end"$
no quote at end$
quote and space at end" $
quote and tab at end"^I$
Your posted code matches every line:
$ perl -ne 'print $_ if $_ =~ /[^"]$/' < test.csv
quote at end"
no quote at end
quote and space at end"
quote and tab at end"
The reason for this becomes apparent when you look at exactly what $_ contains:
$ perl -ne 'print ">>>$_<<<\n" if $_ =~ /[^"]$/' < test.csv
>>>quote at end"
<<<
>>>no quote at end
<<<
>>>quote and space at end"
<<<
>>>quote and tab at end"
<<<
Each line ends with a newline which, not being a double-quote, means /[^"]$/ matches.
You can get around this most easily but simply using the -l switch:
$ perl -lne 'print $_ if $_ =~ /[^"]$/' < test.csv
no quote at end
quote and space at end"
quote and tab at end"
If you look at perlrun, you'll see that's equivalent to chomping each input line and appending a newline (or whatever the current value of $/ is) to each output line:
$ perl -ne 'chomp; print "$_\n" if $_ =~ /[^"]$/' < test.csv
no quote at end
quote and space at end"
quote and tab at end"
[Note: the -l switch is a little more complicated than my simplistic explanation - see the doco for details.]
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