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Sure. No need to do any recursion here. Just count in binary. Here is a version that creates a closure (an anonymous subroutine that holds the needed data inside of itself -- sort of like a tiny "object") that returns the next combination each time it is called:

sub combinations { my @list= @_; my @pick= (0) x @list; return sub { my $i= 0; while( 1 < ++$pick[$i] ) { $pick[$i]= 0; return if $#pick < ++$i; } return @list[ grep $pick[$_], 0..$#pick ]; }; } my $next= combinations( 50..59 ); my @comb; while( @comb= $next->() ) { # do work with @comb here } # Note that the empty set is a valid combination but is # the last combination returned which also indicates "no # more combinations left. So the above loop doesn't bother # processing the empty list. If you want to process the # empty set, then use: my @comb; do { # do work with @comb here } while( @comb= $next->() );

Update: My code finds combinations but the original code finds permutations even though the author asked for combinations. (See (tye)Re: Permutations if you don't know the difference between the two.)

Of course, my favorite way of finding permutations is Permuting with duplicates and no memory.

        - tye (but my friends call me "Tye")

In reply to (tye)Re: Finding all Combinations by tye
in thread Finding all Combinations by narse

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