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I am willing to pose the following: ANYBODY can program, the problem lies in analysing the data you are presented with.

I'll agree with you on the first point, pretty much anybody can learn to program. Too often programmers try to make what their doing look way more complex than it is. This is seen in just about every other profession as well, and doesn't do any good in those professions either. When properly broken down into their smaller components, all tasks are quite simple.

As for the problem being in analyzing the data, well, pretty much anyone can do that too. As with programming, some people are better than others due to more experience, higher natural ability, being more interested in it, and so on. Analyzing data is part of programming, and if there are great data analysts, then there are also great programmers.


In reply to Re: do you know Perl ?, or do you know ? by cjf
in thread do you know Perl ?, or do you know ? by ChOas

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    [Corion]: You'll have to look somewhere esoteric for that. Maybe some tied variable or special dualvar can also trigger that. But it's certainly not a common occurrence
    [Corion]: And on 5.20, the following also outputs no find:perl -wle 'for my $x ("\x{2000}".."\ x{1fffff}") { if( $x && ! length $x ) { warn qq(<$x>); warn length $x; die } }'
    [Corion]: (this time on Unix)
    [hippo]: Understood. I'll have to go through the code and see if it's doing anything fancy with ties, dual-vars or non-scalars. In the end, it's probably a bug though.
    [Corion]: Aaah - you should be able to do this with overload, but I would hit somebody really hard if they constructed objects that are true but the empty string, and you not knowing about the domain knowledge where this makes sense
    [Eily]: you could tie a variable into not having the same value each time, if you like to make people who try to debug your code facepalm
    [Corion]: perl -wle 'package o; use overload q("") => sub {warn "str"; ""}, bool => sub{warn "bool"; 1}; package main; my $o={}; bless $o => o; print "Yay" if ($o && !length($o))'

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