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The qw() operator provides list context already. So
print ( qw(a b c) x 3 );

yields the same result as

@l = qw(a b c); print ( (@l) x 3);

which makes sense imho. An array isn't a list, but a qw() expression is.

update: as a reminder, this is from perlop:

Binary "x" is the repetition operator. In scalar context or if the left operand is not enclosed in parentheses, it returns a string consisting of the left operand repeated the number of times specified by the right operand. In list context, if the left operand is enclosed in parentheses or is a list formed by "qw/STRING/", it repeats the list. If the right operand is zero or negative, it returns an empty string or an empty list, depending on the context.

--shmem

_($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                              /\_¯/(q    /
----------------------------  \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

In reply to Re^3: Why should I use perl 5.10? by shmem
in thread Why should I use perl 5.10? by saintmike

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