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I think all of those are correct, though not particularly useful. They should also prompt (at least) a warning, though I think a catchable exception is better. You also have to be careful to distinguish between a variable containing NaN, and a constant NaN I think. That is, I think the only time any comparison involving a variable containg NaN should result in a true value, is if it is compared against a predefined constant NaN; were one to be provided. Though an isNaN( $x ) function or equivalenly $x->isNan() method would serve the same purpose and be less likely to confuse. Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
In reply to Re^4: NaNs are true (NaN == 0 -> true? Really?)
by BrowserUk
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