select distinct OS,
                RELEASE,
                (select count(1) from $table as y
                                 where x.OS=y.OS and x.RELEASE=y.RELEASE and y.LIKE='Yes'),
                (select count(1) from $table as y
                                 where x.OS=y.OS and x.RELEASE=y.RELEASE and y.LIKE='No')
       from $table as x;