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in reply to Re^4: How to return values from a hash?
in thread How to return values from a hash?

try changing
} elsif ($rfv == 'HASH') {
to
} elsif ($rfv eq 'HASH') {
poj

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Re^6: How to return values from a hash?
by perl-diddler (Chaplain) on Mar 30, 2013 at 14:46 UTC
    Sorry, that was a last minute change. In order to simplify the code for inclusion here, I left out a trivial optimization where I convert HASH to an integer:
    use constant Array => 1; use constant Hash => Array << 1; our %_typemap=(ARRAY=>Array, HASH=>Hash); sub _Var ($$$;$) { # Wrkhorse code for manu +fctrd Vars my ($__, $p, $vn, $wa)=@$_; $_=$__; # must not trash '$_' my $v = $p->{$vn}; # value my $rfv = ref $v; # type(ref) of var my $rfvi = $_typemap{$rfv} || 0; my ($arg, $addrof); if ($wa && $wa eq '&#945;') { $wa=undef, $addrof=1 } if (@_ && !$addrof) { # arg for "setter" $arg = shift; my $refarg = ref $arg; # ref of the arg unless ( defined($p->{$vn}) && defined $arg ){ # unless both de +fined $p->{$vn} = $arg; } elsif ($rfvi == Array) { ## if type(var)==ARRAY, +1 param if ($refarg ne "ARRAY" || (@$arg || @$v)) { push @{$p->{$vn}}, $_[0]; ## convert to "push" } } elsif ($rfvi == Hash) {
    I tried to cut down the amount of code included by cutting out the integer thing...sorry. I didn't want to get dinged for not trying to cut things down...