http://www.perlmonks.org?node_id=1040750


in reply to how to get a subroutine name?

For historic reasons, I would propose to define a sub called __FUNC__ that returns the name of the subroutine in which it was called, see the following example: 

use strict;
use warnings;

sub __FUNC__ { (caller 1)[3] }

sub func {
    print "We are now in ", __FUNC__, "\n";
}
 
func();

[download]

UPDATE: Removed a duplicated "print".

Replies are listed 'Best First'.
Re^2: how to get a subroutine name?
by LanX (Saint) on Jun 26, 2013 at 12:04 UTC
    > For historic reasons,

    Sorry, which historic reasons?

    If you don't like caller's interface - where I sympathize - I'd rather propose something more flexible like returning a hashref:

       DB<116> sub __CALLER__ { 
           my $level = shift;
           my %hash; 
           @hash{qw/package filename line subroutine hasargs wantarray
+ evaltext is_require hints bitmask hinthash/} = caller($level+1); 
           return \%hash 
           }
  DB<130> sub tst { print __CALLER__->{subroutine} }

  DB<131> tst()
main::tst

    [download]
    or 
      DB<136> use Data::Dump qw/dd/

  DB<137> sub tst { dd __CALLER__ }

  DB<138> tst()
{
  bitmask     => "\0\0\0\0\0\0\0\0\0\0\0\0",
  evaltext    => undef,
  filename    => "(eval 108)[multi_perl5db.pl:644]",
  hasargs     => 1,
  hinthash    => undef,
  hints       => 256,
  is_require  => undef,
  line        => 2,
  "package"   => "main",
  subroutine  => "main::tst",
  "wantarray" => 1,
}

    [download]
    Though not sure about using this underscore __NAMESPACE__...

    And I'm pretty sure about reinventing the wheel ...

    ... CPAN is so big and I'm so lazy ;-)

    Cheers Rolf

    ( addicted to the Perl Programming Language)

[reply]
[d/l]
[select]

      I had to think about __LINE__ and __FILE__ etc from the good old times...

      Correction: I was thinking about good old __LINE__ and __FILE__...

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Re^2: how to get a subroutine name?
by clueless newbie (Curate) on Jun 26, 2013 at 12:49 UTC

    5.16 added __SUB__ for this purpose.

    My bad! It returns a coderef.
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      However, __SUB__ returns a reference to the currently running subroutine according to perlsub. Not sure how you will get its name?

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[d/l]

        Sub::Identify?

        Still, that's rather a roundabout way to do things.

        package Cow { use Moo; has name => (is => 'lazy', default => sub { 'Mooington' }) } say Cow->new->name
[reply]

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