http://www.perlmonks.org?node_id=892673

dirtdog has asked for the wisdom of the Perl Monks concerning the following question:

Hi Monks, I'm trying to get the last day of the month from 2 months ago. For example, Since the current month is March i'd like to get a date range of 1/31/2011 to 2/28/2011. And If current month was February..then i'd want 12/31/2010 to 01/31/2011. The code i'm using is below...I really appreciate your help!

#!/usr/bin/env perl use POSIX 'strftime'; my @t = (localtime(time)); #mktime(sec, min, hour, mday, mon, year, wday = 0, yday = 0, isdst = 0 +); my $lastday = POSIX::mktime(0,0,0,0,$t[4],$t[5],0,0,-1); my $lastday_prev = POSIX::mktime(0,0,0,0,$t[3],$t[5],0,0,-1); my @ld_prev = localtime($lastday_prev); my @ld = localtime($lastday); print "ld is $ld[3]\n"; print "ld_prev is $ld_prev[3]\n"; my $monthly_date_beg = strftime('%m/' . $ld_prev[3] . '/%Y', $t[0],$t[ +1], $t[2], $t[3], $t[4]-2, $t[5]); my $monthly_date_end = strftime('%m/' . $ld[3] . '/%Y', $t[0],$t[1], $ +t[2], $t[3], $t[4]-1, $t[5]); rint "beg = $monthly_date_beg\n"; print "end = $monthly_date_end\n";

Replies are listed 'Best First'.
Re: How to get last day of 2 months ago
by Corion (Patriarch) on Mar 11, 2011 at 16:05 UTC

    The key to finding the "last day of a month" is to realize that the "last day" of a month is always one day before the "first day" of the next month. As the date of the first day of a month is easy to construct, you just have to construct the first day of the current month, then go to the last day of the month before. Then extract the year and month of that month, and construct its first day from it. Repeat until you have skipped enough months.

    Personally, I like to use Time::Local and localtime, together with POSIX::strftime to manipulate and create date strings. The more heavyweight and somewhat different approach is to use DateTime, but as I often have to do date calculations, and not always in Perl, the strftime approach has worked more often for me than the DateTime approach.

      Thank you all for the replies. I did figure out what i was doing wrong..I had

      $t[3]

      ..when i should have had

      $t[4]-1
      use POSIX 'strftime'; my @t = (localtime(time)); my $lastday = POSIX::mktime(0,0,0,0,$t[4],$t[5],0,0,-1); my $lastday_prev = POSIX::mktime(0,0,0,0,$t[4]-1,$t[5],0,0,-1); my @ld_prev = localtime($lastday_prev); my @ld = localtime($lastday); my $monthly_date_beg = strftime('%m/' . $ld_prev[3] . '/%Y', $t[0],$t[ +1], $t[2], $t[3], $t[4]-2, $t[5]); my $monthly_date_end = strftime('%m/' . $ld[3] . '/%Y', $t[0],$t[1], $ +t[2], $t[3], $t[4]-1, $t[5]); print "beg = $monthly_date_beg\n"; print "end = $monthly_date_end\n";
Re: How to get last day of 2 months ago
by Anonymous Monk on Mar 11, 2011 at 15:20 UTC
Re: How to get last day of 2 months ago
by JavaFan (Canon) on Mar 11, 2011 at 15:38 UTC
    sub last_day_2_months_ago {31;} # Correct most of the time
Re: How to get last day of 2 months ago
by Anonymous Monk on Mar 11, 2011 at 17:01 UTC
    #!/usr/bin/perl use strict; use warnings; use 5.012; use Time::Local qw( timegm_nocheck ); my ($y, $m, $d) = (localtime)[5,4,3]; my $start = scalar gmtime(timegm_nocheck(0,0,0, (1-1), $m-1, $y)); my $end = scalar gmtime(timegm_nocheck(0,0,0, (1-1), $m, $y)); say "Today is " . localtime; say join "\n", $start, $end;
    ** prints
    Today is Fri Mar 11 11:56:50 2011 Mon Jan 31 00:00:00 2011 Mon Feb 28 00:00:00 2011