Re^3: .vimrc for perl programmers

in reply to Re^2: .vimrc for perl programmers
in thread .vimrc for perl programmers

can you provide an example where this (undocumented?) syntax makes a difference?

Comment on Re^3: .vimrc for perl programmers

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Re^4: .vimrc for perl programmers by demerphq (Chancellor) on Nov 01, 2006 at 17:50 UTC
Looks like its been superficially improved so there is no difference anymore, which is good. But the output is still wrong, which is bad. For `$x=\$y; $y=\$x;` the raw call to `Data::Dumper->Dump([$x,$y])` used to produce: `$VAR1 = [ \\$VAR1->[0], ${$VAR1->[0]} ];` [download] But now it produces what Data::Dumper::Dumper (and what the sub{\@_} trick does) produce: `$VAR1 = \\$VAR1; $VAR2 = ${$VAR1};` [download] Wheras `Data::Dump::Streamer::Dump` produces the correct output: `$REF1 = \$REF2; $REF2 = \$REF1;` [download] Hope that explains things. --- $world=~s/war/peace/g	[reply] [d/l] [select]

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Re^4: .vimrc for perl programmers
by demerphq (Chancellor) on Nov 01, 2006 at 17:50 UTC

Looks like its been superficially improved so there is no difference anymore, which is good. But the output is still wrong, which is bad. For $x=\$y; $y=\$x; the raw call to Data::Dumper->Dump([$x,$y]) used to produce:

$VAR1 = [
          \\$VAR1->[0],
          ${$VAR1->[0]}
        ];
[download]

But now it produces what Data::Dumper::Dumper (and what the sub{\@_} trick does) produce:

$VAR1 = \\$VAR1;
$VAR2 = ${$VAR1};
[download]

Wheras Data::Dump::Streamer::Dump produces the correct output:

$REF1 = \$REF2;
$REF2 = \$REF1;
[download]

Hope that explains things.

---
$world=~s/war/peace/g

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