http://www.perlmonks.org?node_id=705321

Look at the following snippet.

perl -e 'open strict, ">&", STDOUT or die; use strict; print strict fo +obar, "\n";'

This prints foobar so clearly foobar is interpretted as a bareword. However, we use strict, so that should disallow barewords. Why is this? (The title of the post can give a hint.)

Replies are listed 'Best First'.
Re: A feature of use
by ambrus (Abbot) on Aug 20, 2008 at 19:57 UTC

    In fact, even this works.

    perl -e 'if (0) { open strict; } use strict; print STDOUT foobar, "\n" +;'
Re: A feature of use
by jdalbec (Deacon) on Aug 20, 2008 at 22:45 UTC
Re: A feature of use
by ambrus (Abbot) on Jul 18, 2016 at 09:34 UTC