d-mmm-yyyy to DOY (day of year)

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Hi, hopefully someone might be able to help as I've been searching all night for a solution to this, and am running out of time.

I have to convert this date field (or add another field) to the day of year (DOY). It is currently in d-mmm-yyyy.

By Day of year, I mean 1st January 2013 would be 1. 2nd January would be 2.

Here is a snippet of my very large (7,000,000 row table)

Date,GridID,new_l,O_Count,B_Count,E_Count,P_Count,C_Count,O_Y,B_Y,E_Y,
+P_Y,C_Y,DayRain,Antecedent20RainSum,Antecedent10RainSum,Antecedent05R
+ainSum,Antecedent02RainSum
1-Apr-2012,615265,2.4,0,0,0,0,0,0,0,0,0,0,0.00,0.00,0.00,0.00,0.00
2-Apr-2012,615265,2.4,0,0,0,0,0,0,0,0,0,0,0.00,0.00,0.00,0.00,0.00
3-Apr-2012,615265,2.4,0,0,0,0,0,0,0,0,0,0,11.60,11.60,11.60,11.60,11.6
+0
[download]

many, many thanks

Tim

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