Re^3: Why does eof have a prototype?

[ikegami]

That certain operators (eof, open, etc.) have prototypes that aren't adequate for representing the syntax of the operator is the premise of the question.

For example,

• An overridden eof operator can't distinguish whether it was was called as eof or eof() while the real operator does.

• open( STDERR , ">&=", STDOUT ) is perfectly valid with the real operator, but throws a strict error with an overridden open.

  $ perl <<'.'
  use strict;
  open( STDERR , ">&=", STDOUT );
  BEGIN { *CORE::GLOBAL::open = sub (*;$@) { } }
  open( STDERR , ">&=", STDOUT );
  .
  Bareword "STDOUT" not allowed while "strict subs" in use at - line 4.
  Execution of - aborted due to compilation errors.
  

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Upd: Fixed accidental double negation.

[LanX]

Filehandles are still too voodoo for me, I hoped something like this could fix that problem...

use constant STDERR => \*STDERR;
use constant STDOUT => \*STDOUT;