in reply to Re^2: sed command with variable in perl
in thread sed command with variable in perl

Hi AnomalousMonk

....... using warning; first of all , i used that line before ( use strict; use warning;) at the top of my Perl code and for this reason I omit them. I think i should explain a little bit about my code. I have to m file (from matlab) and I just want to make them work automate as a software. I am very very new into Perl. For this reason I used linux shell commands and it worked fine. Now , There is problem with my code.

.... File name argument I will put my file name in the correct place , thank you.

..... substitution operation without something to substitute As i mentioned before, I have two files each of them has spciefic SOL number which I used grep command to count them and then use it as a variable. $cmd =("grep -e HW1 myhalf1.pdb | wc -l > text1.txt") ; open FILE, "<text1.txt"; my $sol1= do {local $/; <FILE>}; print p ("sol1=$sol1"); As you see I have it before. in the code, which you had posted i just omit this line my $sol1 = 'my new stuff'; because i introduce my variable before. and the next line which have $sol1 is remained intact. s{ (SOL) ^\n* }{$1 $sol1}xmsg;

......about errors i ve added the code into my .pl file and run it. After that I check error_log file in the server and there is no warning. I have just changed the line into this my $filename_in = ''; no error.even not making another file. and i ve checked the file permission problem about the permission.