http://www.perlmonks.org?node_id=45928

Ri-Del has asked for the wisdom of the Perl Monks concerning the following question: (directories)

I would like to read the names of all the files in a directory of mine into an array so that I can convert each file name into a link to that file. Currently I am doing this in the following manner. I read the "dir.dat" file with the following command, "ls > dir.dat." I should like rather to get the current directory's files from within the script rather than having to do that command everytime I want to regenerate the html. How might I do this?
#!/usr/local/bin/perl use strict; @filename; $i = 0; $total; open(INFILE,"dir.dat"); while($filename[$i] = <INFILE>){ chop($filename[$i]); $filename[$i] =~ s/\*//g; $i++; $total++; } $error = open(OUTFILE,"> dict.html"); if(!$error){ print("ERROR\n"); exit(0); } print(OUTFILE "<HTML>\n <HEAD>\n </HEAD>\n <BODY TEXT=#00ff00 LINK=# +00ff00 VLINK=#00ff00 BGCOLOR=#000000 alink=00FF00>\n"); for($i=0;$i<=$total;$i++){ print(OUTFILE "<A HREF=\"$filename[$i]\">$filename[$i]</A><BR>\n"); } print(OUTFILE "</BODY>\n</HTML>\n"); close(OUTFILE);

Originally posted as a Categorized Question.