http://www.perlmonks.org?node_id=466451


in reply to Re: Fastest way to calculate hypergeometric distribution probabilities (i.e. BIG factorials)?
in thread Fastest way to calculate hypergeometric distribution probabilities (i.e. BIG factorials)?

BTW, do you really mean "the odds"? Or do you want the probability p? [...] (The odds are (1 p)/p.)

Hmm, if the probability is 25%, I'd read that as implying "the odds are 3". But that isn't right: the odds are "3 to 1 against", which means the same as 25% - in fact I'd consider it reasonable even to say "the odds are 25%".

I'm not sure if there is a name for what (1-p)/p represents, but I don't think "the odds" is it.

Hugo