in reply to Algorithm for cancelling common factors between two lists of multiplicands
Hi BrowserUK,
I'm not understanding what you mean by cancelling out. Can you explain a bit more thoroughly? I see you've updated the original node, but it's still not clear to me. If an item in b is a factor of an item in a, should both be eliminated? Or if they have a factor in common? Or...?
Also, will the arrays be sorted, as they are in your example?
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