in reply to Re^4: Recursive substitution
in thread Recursive substitution
I want recursion.
Sorry, but you can't execute another s/// without /e, (?{}) or (??{}). Recursion is out.
As for a solution without recursion, I don't know of any.
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Re^6: Recursive substitution
by JadeNB (Chaplain) on Nov 10, 2009 at 19:33 UTC | |
by ikegami (Patriarch) on Nov 10, 2009 at 19:37 UTC |
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