in reply to Re^5: Efficient way to replace a set of values with another set of values
in thread Efficient way to replace a set of values with another set of values
You were looking for:
s/^(\d+)/$n=$1;$l="a";$l++while--$n;$l/meg
Doesn't cope with 0 especially well.
perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'
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