in reply to Re^2: Equivalency of Code
in thread Equivalency of Code

The point is that $x++ and $x += 1 don't just fiddle with the value of $x. Those statements also have values themselves. If a bit of code is to be equivalent to another, then it needs to both have the same side-effects and the same value as the other does.

I try not to think about operator overloading or tieing :-)

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Re^4: Equivalency of Code
by Anonymous Monk on Feb 08, 2005 at 10:57 UTC
    The statements are presented where in void context - and in void context, there's no return value.