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Re: Strange interaction between print and the ternary conditional operator

by kcott (Bishop)
on Feb 20, 2020 at 07:22 UTC ( #11113231=note: print w/replies, xml ) Need Help??

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  1. or download this
    $ perl -MO=Deparse,-p -e 'print "foo, " . (1 ? "yes" : "no") . " bar";
    +'
    print('foo, yes bar');
    -e syntax OK
    
  2. or download this
    $ perl -MO=Deparse,-p -e 'print (1 ? "yes" : "no") . " bar";'
    (print('yes') . ' bar');
    -e syntax OK
    
  3. or download this
    $ perl -e '$x = print "foo, " . (1 ? "yes" : "no") . " bar"; print "\n
    +$x\n"'
    foo, yes bar
    1
    
  4. or download this
    $ perl -e '$x = print (1 ? "yes" : "no") . " bar"; print "\n$x\n"'
    yes
    1 bar
    
  5. or download this
    use strict;
    use warnings;
    
  6. or download this
    $ perl -e 'use strict; use warnings; print (1 ? "yes" : "no") . " bar"
    +;'
    print (...) interpreted as function at -e line 1.
    Useless use of concatenation (.) or string in void context at -e line 
    +1.
    yes
    

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