Re: ~~ and list literal

What are you trying/hoping to do?

$ perl -MO=Deparse,-p -
print( "x" ~~ ("x", "y", "z") );
^Z
print(('x' ~~ ('???', '???', 'z')));
- syntax OK
[download]

??? means value is discarded, meaning it is same as 'x' ~~ 'z'

Aside from changing the code to "x" ~~ ["x", "y", "z"], is there another way?

Yeah, without ~~

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Re^2: ~~ and list literal by Anonymous Monk on Oct 25, 2012 at 11:38 UTC
I was trying to find an element in a list, like in an array with `"x" ~~ @ary` (which works).	[reply] [d/l]