nonsequitur has asked for the wisdom of the Perl Monks concerning the following question:
I have been trying to use the regex substitution modifier "r" to work with no success. I finally tried running the examples from perlrequick and cannot get them to work either. This example is from the section titled "The non-destructive modifier s///r".
$x = "I like dogs."; $y = $x =~ s/dogs/cats/r; print "$x $y\n"; # prints "I like dogs. I like cats."
When I run it I get this error.I get the same error using strict and declaring the variables.
Bareword found where operator expected at r.pl line 2, near "s/dogs/ca +ts/r" syntax error at r.pl line 2, near "s/dogs/cats/r"
Can anyone tell me what's wrong?
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Replies are listed 'Best First'. | |
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Re: Regex substitution modifier /r
by davido (Cardinal) on Dec 15, 2012 at 00:35 UTC | |
Re: Regex substitution modifier /r
by toolic (Bishop) on Dec 15, 2012 at 00:40 UTC | |
Re: Regex substitution modifier /r
by Anonymous Monk on Dec 15, 2012 at 04:34 UTC | |
Re: Regex substitution modifier /r
by nonsequitur (Pilgrim) on Dec 15, 2012 at 09:41 UTC |
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