Re: Using special characters in left part of a regex match?

[moritz]

$var[$j] =~ s/\.\.\./\.\+/g;

The right half of an s/// substitution is not a regex, but a mere string. So if you want to construct .+ in the replacement, you need to write it as .+ and not at \.\+.

[LanX]

> you need to write it as .+ and not at \.\+.

He doesn't need to, it's no error.

But it's better readable w/o escaping.