Re: how to use perl variable in system command to run on unix

[chromatic]

$grep_date won't interpolate in the singly-quoting q() construct. When you change to a double-quoting construct, be sure to escape the dollar sign in awk's $9 argument.

[tousifp]

Thanks Chromatic. I changed this line as said : my $files=system(qq(cd /waslogs1/vfoneLog/cposapp && ls -lrt | grep -i "$grep_date" | awk '{ print \$9 }' > /home/cpos/CRM_Reports/timelogic/filelist.txt)); Its working now. But can you explain me what was the problem with previous line.

And what if I use :

my $cmd=q(cd /waslogs1/vfoneLog/cposapp && ls -lrt | grep -i "$grep_da
+te" | awk '{ print $9 }' > /home/cpos/CRM_Reports/timelogic/filelist.
+txt);

my $files=system($cmd);

This is still not working

[Arunbear]

q does not expand variables, for that you need qq e.g.

% perl -E '$x = "hello"; say q($x)'
$x
% perl -E '$x = "hello"; say qq($x)'
hello

[tousifp]

Thank you very much. But why $9 is escaped? Me new to perl !!!