Re: How can one find unique elements from arrays using a LOOP?

[choroba]

You are assigning a single element to an array, namely a value from a (non-existent) hash:

@arr = $p{$num};

Using strict would have told you.

Also,

push @p, @x;
push @p, @y;

is effectively the same as

push @p, $_ for @x, @y;

Why are you pushing array references in the first example, but arrays in the second one?

[pajout]

Simply


push @p, @x, @y;

:)

[choroba]

I had the feeling the OP might still understand that as

push @p, \@x, \@y

[supriyoch_2008]

Hi choroba,

Thank you for your suggestions and prompt reply. My problem appears to be solved. Your last sentence (question) has been very constructive and ignited my thinking. It has helped me to sort out the problem. I have corrected the script m.pl and it goes as follows. I am grateful to you.

With regards,

Here goes the code m.pl:

#!/usr/bin/perl 
use warnings; 

use List::Compare;   # Use of module

@x= qw/a b/; 
@y= qw/a c/; 
@z= qw/a d/;  

  push @s,\@x,\@y,\@z; 

  $num_ele=@s; 
       
print "\n 
 Array s: @s\n
 No. of Elements: $num_ele\n"; 

  $all= List::Compare->new(@s); # module 

@unq_x=$all->get_unique(0);    
@unq_y=$all->get_unique(1);
@unq_z=$all->get_unique(2);

print "
 unq_x: @unq_x\n
 unq_y: @unq_y\n
 unq_z: @unq_z\n\n"; 

exit;

The results of m.pl are (correct):

C:\Users\x\Desktop>m.pl

 Array s: ARRAY(0x320b14) ARRAY(0x320b64) ARRAY(0x3305d4)

 No. of Elements: 3

 unq_x: b

 unq_y: c

 unq_z: d