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Re: Finding divisors from factors

by danaj (Friar)
on Oct 08, 2014 at 20:35 UTC ( [id://1103220]=note: print w/replies, xml ) Need Help??

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  1. or download this
    sub divisors {
      my($n,@f) = @_;
      my @d = (1);
    ...
      @d = sort { $a <=> $b } @d;
      @d;
    }
    

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