Re: Regex \. help

[Loops]

Something using zero width negative look ahead (?!) should work:

my @t = qw( regex regex.1 regex.12 regex.1a regex.a regex.abc regex.a1
+ oregex.2 );
for (@t) {
    print $_;
    print ' matches!' if /^regex(?!\.[^\d])(\.\d*)?/;
    print "\n";
}

gives:

regex matches!
regex.1 matches!
regex.12 matches!
regex.1a matches!
regex.a
regex.abc
regex.a1
oregex.2

Checkout the "Look-Around Assertions" section in the perlre documentation. In the example above, the negative look-ahead says fail if the next characters are a period followed by anything that isn't a digit.

[AnomalousMonk]

Loops: You read the OP a bit more slowly and carefully, and came closer, I think, to answering codz67's question as a result. But the  (\.\d+)? is redundant for the given inputs and outputs if the negative look-ahead is used. (Had it been needed, it would probably have been better as a  (?:...) non-capturing group.)

c:\@Work\Perl>perl -wMstrict -le
"my @t = qw( regex regex.1 regex.12 regex.1a regex.a regex.abc regex.a
+1 oregex.2 );
 for (@t) {
   printf qq{'$_'};
   printf ' matches!' if /^regex(?!\.[^\d])/;
   print '';
   }
"
'regex' matches!
'regex.1' matches!
'regex.12' matches!
'regex.1a' matches!
'regex.a'
'regex.abc'
'regex.a1'
'oregex.2'

[Loops]

Hi,

Yeah you're right about that. I confess to removing the non-capturing annotation for simplicity sake. Here's a slightly different version where the \d* isn't redundant:

my @t = qw( regex regex. regex.1 regex.12 regex.1a regex.a regex.abc r
+egex.a1 oregex.2 );
say s/^regex(?!\.[^\d])(\.\d*)?/|$&|/r for (@t);

|regex|
|regex.|
|regex.1|
|regex.12|
|regex.1|a
regex.a
regex.abc
regex.a1
oregex.2

[codz67]

#!/usr/bin/perl
@filename = `ls  | grep  "^regex\.[0-9]"`;
print @filename;

    ...

prints regex.1. I need it to print regex and regex.1:

#!/usr/bin/perl
@filename = `ls  | grep  "^regex\.?[0-9]"`;
print @filename;

Doesnt print anything.

Shouldnt the ? match the . zero or more times? If so why doesnt it print regex and regex.1 As for the .abc I need that to be excluded when it greps. So regex.abc and regex.xyz wont print.

Thank you for the help so far, I am still stuck on making this work. I will continue to try to make this work, if anyone could assist further I would be very thankful.